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Home » \[ (2x - 1)(x - 1) = 0. \] - SUpost

\[ (2x - 1)(x - 1) = 0. \] - SUpost

📅 July 5, 2026 👤 scraface

Jul 05, 2026

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📌 We need the two non-prime rolls to both be even → 2 choices each → $ 2 \times 2 = 4 $ even-even combinations

📌 Odd contributions only matter if we have odd primes, but here none → all even

📌 So for Case 1:

📌 6 position choices

📌 1 prime assignment (2,2)

📌 4 non-prime even pairs

📌 → $ 6 \times 1 \times 4 = 24 $ sequences

📌 But wait: $ \binom{4}{2} = 6 $ ways to place the primes → yes

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