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Total arrangements: $56 \cdot 10 \cdot 120 = 67200$.
Thus, the number of distinct arrangements is $oxed{67200}$.
Question: A genetic modification researcher is testing 4 genetically edited maize varieties under drought conditions and 6 conventional varieties. If 5 varieties are selected at random for a large-scale field trial, what is the probability that exactly 2 of the selected varieties are genetically edited?

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📰 Solution: We are given 5 distinct parts: A, B, C, D, and E, and we are to count the number of permutations where A appears before B and C appears before D. 📰 First, the total number of permutations of 5 distinct parts is $5! = 120$. 📰 In any random permutation, the relative order of A and B is equally likely to be A before B or B before A. So, exactly half of the permutations have A before B. Similarly, exactly half have C before D.