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\text{Final Mass} = \text{Initial Mass} \times (1 - \text{Decay Rate})^n
where \( \text{Decay Rate} = 0.12 \) and \( n = 5 \).
\text{Final Mass} = 200 \times (1 - 0.12)^5 = 200 \times 0.52822 \approx 105.644

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