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Home » \[ \frac39210000 = 0.0392 \text liters \] - SUpost

\[ \frac39210000 = 0.0392 \text liters \] - SUpost

📅 July 6, 2026 👤 scraface

Jul 06, 2026

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📌 Evaluate \( f(1) \):

📌 \( f(1) = 2(1)^2 - 1 - 5 = 2 - 1 - 5 = -4 \).

📌 Thus, \( f(1) = -4 \) after removing the discontinuity.

📌 Find the area enclosed by the curves \( y = x^2 \) and \( y = 4x - x^2 \).

📌 Set the equations equal to find intersection points:

📌 \( x^2 = 4x - x^2 \Rightarrow 2x^2 - 4x = 0 \Rightarrow 2x(x - 2) = 0 \).

📌 So, \( x = 0 \) and \( x = 2 \).

📌 The area is \( \int_0^2 [(4x - x^2) - x^2] \, dx = \int_0^2 (4x - 2x^2) \, dx \).

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