Get Unlocked! The Best Dividend Tracker App That Saves You Real Money Today!

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Get Unlocked! The Best Dividend Tracker App That Saves You Real Money Today!

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$ n^3 \equiv 888 \pmod{8} $. Since $888 \div 8 = 111$, $888 \equiv 0 \pmod{8}$.
So $ n^3 \equiv 0 \pmod{8} $, which implies $ n \equiv 0 \pmod{2} $, and in fact $ n $ must be divisible by $2$. But to get $n^3 \equiv 0 \pmod{8}$, $n$ must be divisible by $2$, and checking small cubes mod $8$: $0^3 = 0$, $2^3 = 8 \equiv 0$, $4^3 = 64 \equiv 0$, $6^3 = 216 \equiv 0$. So all even $n$ satisfy $n^3 \equiv 0 \pmod{8}$. So $ n \equiv 0 \pmod{2} $ is sufficient,
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