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eq b $ implies $ heta
eq \phi $, so $ S $ is purely imaginary. However, the original question may expect a real value. Re-examining:
Let $ S = rac{(a + b)^2 + (a - b)^2}{a^2 - b^2} = rac{2a^2 + 2b^2}{a^2 - b^2} $. Let $ a = 1 $, $ b = i $:

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