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How Long Is the Notebook - SUpost

📅 July 5, 2026 👤 scraface

Jul 05, 2026

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-3b = 4a + 5 \quad \Rightarrow \quad b = -rac{4a + 5}{3}
Thus, all vectors \(egin{bmatrix} a \ -rac{4a + 5}{3} \end{bmatrix}\...
To write a specific solution, choose \(a = -1\):
b = -rac{4(-1) + 5}{3} = -rac{-4 + 5}{3} = -rac{1}{3}
So one such vector is:
\mathbf{v} = egin{bmatrix} -1 \ -rac{1}{3} \end{bmatrix}
However, since the problem asks for *a* vector, the general solution i...
oxed{egin{bmatrix} -1 \ -rac{1}{3} \end{bmatrix}}
For a positive constant \(c\), a bioinformatician models cyclic gene e...
ho, heta, \phi)\), find the shape described by the equation \(

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