Saving as a Power BI Project in Power BI Desktop is currently in preview, and you must enable it in Preview features. Go to File > Options and settings > Options > Preview features and check.

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Open Power BI Desktop. Go to the "File" menu. Select "Options and settings" and then "Options." 4. In the Options window, navigate to the "Preview features" section. 5. Check the box next.

Understanding the Context

Saving as a PBIP using PBIR is currently in preview. Before giving it a try, you must first enable it in Power BI Desktop: go to File > Options and settings > Options > Preview features and check.

You must first enable the feature in Power BI Desktop preview features. Go to File > Options and settings > Options > Preview features. Check the box next to Store reports using enhanced.

Enable Preview Feature: Go to File Options Preview Features, then check Power BI Project (.pbip) Save as PBIP: Use Save As Power BI Project (.pbip) to generate folder structure with.

Enable the Preview Feature: In Power BI Desktop, navigate to File > Options and settings > Options > Preview features and enable "Power BI Project save format".

Key Insights

Power BI Desktop must be configured to support the new .pbip format for seamless Fabric integration. Steps: Figure: Enable Power BI Project (.pbip) Format. Configure parameters in Power Query Editor to.

Saving as a Power BI Project file is in Preview. To use this feature first go to File > Optionsandsettings > Options > Preview features and check the box next to Power BI Project (.pbip).

You must first enable the feature in Power BI Desktop preview features. Go to File > Options and settings > Options > Preview features. Check the box next to Store reports using enhanced.

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📰 Solution: To find when the gears align again, we compute the least common multiple (LCM) of their rotation periods. Since they rotate at 48 and 72 rpm (rotations per minute), the time until alignment is the time it takes for each to complete a whole number of rotations such that both return to start simultaneously. This is equivalent to the LCM of the number of rotations per minute in terms of cycle time. First, find the LCM of the rotation counts over time or convert to cycle periods: The time for one rotation is $ \frac{1}{48} $ minutes and $ \frac{1}{72} $ minutes. So we find $ \mathrm{LCM}\left(\frac{1}{48}, \frac{1}{72}\right) = \frac{1}{\mathrm{GCD}(48, 72)} $. Compute $ \mathrm{GCD}(48, 72) $: 📰 Prime factorization: $ 48 = 2^4 \cdot 3 $, $ 72 = 2^3 \cdot 3^2 $, so $ \mathrm{GCD} = 2^3 \cdot 3 = 24 $. 📰 Thus, the LCM of the periods is $ \frac{1}{24} $ minutes? No — correct interpretation: The time until alignment is the least $ t $ such that $ 48t $ and $ 72t $ are both integers and the angular positions coincide. Actually, the alignment occurs at $ t $ where $ 48t \equiv 0 \pmod{360} $ and $ 72t \equiv 0 \pmod{360} $ in degrees per rotation. Since each full rotation is 360°, we want smallest $ t $ such that $ 48t \cdot \frac{360}{360} = 48t $ is multiple of 360 and same for 72? No — better: The number of rotations completed must be integer, and the alignment occurs when both complete a number of rotations differing by full cycles. The time until both complete whole rotations and are aligned again is $ \frac{360}{\mathrm{GCD}(48, 72)} $ minutes? No — correct formula: For two periodic events with periods $ T_1, T_2 $, time until alignment is $ \mathrm{LCM}(T_1, T_2) $, where $ T_1 = 1/48 $, $ T_2 = 1/72 $. But in terms of complete rotations: Let $ t $ be time. Then $ 48t $ rows per minute — better: Let angular speed be $ 48 \cdot \frac{360}{60} = 288^\circ/\text{sec} $? No — $ 48 $ rpm means 48 full rotations per minute → period per rotation: $ \frac{60}{48} = \frac{5}{4} = 1.25 $ seconds. Similarly, 72 rpm → period $ \frac{5}{12} $ minutes = 25 seconds. Find LCM of 1.25 and 25/12. Write as fractions: $ 1.25 = \frac{5}{4} $, $ \frac{25}{12} $. LCM of fractions: $ \mathrm{LCM}(\frac{a}{b}, \frac{c}{d}) = \frac{\mathrm{LCM}(a, c)}{\mathrm{GCD}(b, d)} $? No — standard: $ \mathrm{LCM}(\frac{m}{n}, \frac{p}{q}) = \frac{\mathrm{LCM}(m, p)}{\mathrm{GCD}(n, q)} $ only in specific cases. Better: time until alignment is $ \frac{\mathrm{LCM}(48, 72)}{48 \cdot 72 / \mathrm{GCD}(48,72)} $? No.