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Now substitute these values back into the equation: - SUpost

📅 July 6, 2026 👤 scraface

Jul 06, 2026

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📝 Recent Posts

\[ 1.08 \]
Height after 5 weeks:
\[ 50 \times (1.08)^5 = 50 \times 1.46933 \approx 73.47 \, \text{cm} \...
#### 73.47
A journalist writes a series of 8 articles. The first article is 1,100...
This is a geometric series with first term \( a = 1,100 \), ratio \( r...
Sum:
\[ S = a \frac{r^n - 1}{r - 1} = 1,100 \times \frac{(1.05)^8 - 1}{0.05...
\[ (1.05)^8 \approx 1.47746 \]
\[ S = 1,100 \times \frac{1.47746 - 1}{0.05} = 1,100 \times \frac{0.47...

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