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Home » Ratio = 50 / 0 → still undefined. - SUpost

Ratio = 50 / 0 → still undefined. - SUpost

📅 July 5, 2026 👤 scraface

Jul 05, 2026

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\[ u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Wobei \( a = 2 \), \( b = 3 \), \( c = -2 \):
\[ u = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 2 \cdot (-2)}}{2 \cdot 2} \]
\[ u = \frac{-3 \pm \sqrt{9 + 16}}{4} \]
\[ u = \frac{-3 \pm 5}{4} \]
Also sind die Lösungen:
\[ u = \frac{2}{4} = \frac{1}{2} \quad \text{und} \quad u = \frac{-8}{...
Da \( \sin \theta = -2 \) keinen gültigen Wert im Bereich \([-1, 1]\)...
\[ \sin \theta = \frac{1}{2} \]
Finde alle Winkel \( \theta \

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