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Home » Solving for \( w \): \( w^2 = \frac1923 = 64 \). - SUpost

Solving for \( w \): \( w^2 = \frac1923 = 64 \). - SUpost

📅 July 6, 2026 👤 scraface

Jul 06, 2026

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x_1 = \frac{12 + 6}{6} = \frac{18}{6} = 3
x_2 = \frac{12 - 6}{6} = \frac{6}{6} = 1
Thus, the roots of the equation are \(\boxed{1 \text{ and } 3}\).
An urban ecology researcher is analyzing the growth of green spaces mo...
To find \(f(2)\) for the function \(f(x) = 2x^3 - 5x^2 + 3x - 1\), sub...
f(2) = 2(2)^3 - 5(2)^2 + 3(2) - 1
Calculate each term separately:
2(2)^3 = 2 \times 8 = 16
-5(2)^2 = -5 \times 4 = -20
3(2) = 6

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Comme \( n \) doit être un entier, \( n = 9 \).
#### 9
Question 7
Un cercle a une circonférence de \( 31.4 \) cm. Trouver l’aire du cerc...
Solution 7
Circonférence \( C = 2\pi r = 31.4 \).
Résoudre pour \( r \) :
r = \frac{31.4}{2\pi} = \frac{31.4}{6.28} \approx 5 \text{ cm}
Aire \( A = \pi r^2 \) :
A = \pi \times 5^2 = 25\pi \approx 78.5 \text{ cm}^2

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