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the circle at hermann park - SUpost

📅 July 6, 2026 👤 scraface

Jul 06, 2026

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📝 Recent Posts

k \cdot \frac{\sqrt{3}}{2} = 4\pi r^2 \frac{dr}{dt}
Solving for $ \frac{dr}{dt} $:
\frac{dr}{dt} = \frac{k \sqrt{3}}{8\pi r^2}
The rate of volume increase is given directly as $ \frac{dV}{dt} = k \...
\frac{dV}{dt} = \frac{k\sqrt{3}}{2}
Thus, the rate of volume increase at $ \theta = 60^\circ $ is $ \boxed...
Question: A data analyst plots a triangle on a coordinate plane with s...
Solution: The triangle has side lengths $ a = 13 $, $ b = 14 $, and $...
The altitude corresponding to a side is $ h = \frac{2A}{\text{side}} $...
h_{\text{longest}} = \frac{2 \cdot 84}{13} = \frac{168}{13} \approx 12...

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