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Home » -v_2 = -2 \implies v_2 = 2 - SUpost

-v_2 = -2 \implies v_2 = 2 - SUpost

📅 July 5, 2026 👤 scraface

Jul 05, 2026

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$-\omega -3 -2\omega + 2 + \omega + 5 = (-\omega -2\omega + \omega) +...
So \(a\omega + b = -2\omega + 4 \Rightarrow a = -2, b = 4\)
But earlier synthetic evaluation said \(3\omega + 4\)? Let's recompute...
Expression:
$x^4 + 3x^3 - 2x^2 + x + 5$
At $x = \omega$:
$(-\omega) + 3(-1) + (-2)(\omega - 1) + \omega + 5 = -\omega - 3 -2\om...
Combine: $(-\omega -2\omega + \omega) = -2\omega$, $(-3 + 2 + 5) = 4$...
So $a = -2$, $b = 4$
But let's verify with another point or use polynomial identity.

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