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Home » x^3 + y^3 = (x + y)^3 - 3xy(x + y) - SUpost

x^3 + y^3 = (x + y)^3 - 3xy(x + y) - SUpost

📅 July 6, 2026 👤 scraface

Jul 06, 2026

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Question**: If \( \log_2(x) + \log_2(x - 2) = 3 \), find \( x \).
Combine logs: \( \log_2(x(x - 2)) = 3 \).
So, \( x(x - 2) = 2^3 = 8 \).
\( x^2 - 2x - 8 = 0 \).
Factor: \( (x - 4)(x + 2) = 0 \).
\( x = 4 \) or \( x = -2 \).
But \( x > 2 \) for log to be defined, so \( x = 4 \).
The solution is \( x = 4 \).
Question**: A rectangle has a perimeter of 48 cm and a length that is...
Let width = \( w \), length = \( 2w \).

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