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Home » z = 30^\circ, \quad z = 60^\circ - SUpost

z = 30^\circ, \quad z = 60^\circ - SUpost

📅 July 5, 2026 👤 scraface

Jul 05, 2026

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\frac{1^2}{1} + \frac{1^2}{1} + \frac{1^2}{1} = 1 + 1 + 1 = 3
Thus, the minimum value is \( \boxed{3} \).Question:
A linguist studying the evolution of sign language observes that a tri...
To find the area of the triangle with sides \(a = 13\), \(b = 14\), an...
The area \(A\) is given by:
A = \sqrt{s(s-a)(s-b)(s-c)} = \sqrt{21(21-13)(21-14)(21-15)}
A = \sqrt{21 \times 8 \times 7 \times 6} = \sqrt{7056} = 84
r = \frac{A}{s} = \frac{84}{21} = 4
Thus, the radius of the inscribed circle is \(\boxed{4}\).
A pharmacologist developing new drugs visualizes molecular bonds as a...

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A_{\text{triangle}} = \frac{1}{2}ab = r \cdot s
where \( r = c = 2 \) and \( s = \frac{a + b + z}{2} \) is the semi-pe...
Using the identity for right triangles:
c = \frac{a + b - z}{2} \Rightarrow a + b = 2c + z = 4 + 10 = 14
Now, the semi-perimeter:
s = \frac{a + b + z}{2} = \frac{14 + 10}{2} = 12
Then, the area of the triangle is:
A_{\text{triangle}} = r \cdot s = 2 \cdot 12 = 24
Now, the ratio is:
\frac{A_{\text{circle}}}{A_{\text{triangle}}} = \frac{4\pi}{24} = \fra...

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